The equation is .
Solve the eqation:
\ (Original equation)
(Cross product)
(Distributive property:
)
(Subtract
from each side)
(Apply additive inverse property :
)
(Divide each side by
)
(Cancel common terms)
Therefore,the value of is
.
Check the solution by substituting -value in the equation.
(Original equation)
(Substitute
in the equation)
(Simplify)
Therefore,the equation is satified at .
So, the value of is
.
The value of is
.