The equation is .
Solve the equation.
\ (Original equation)
(Subtract
from each side)
(Apply additive inverse property:
)
(Subtraction:
)
(Square on each side)
(Cancel square and root terms)
(Subtract
from each side)
(Apply additive inverse property:
)
(Subtraction:
)
Therefore, the value of is
.
Check the solution for -values:
(Original equation)
(Substitute
in the equation)
(Addition:
)
(Substitute:
)
(Substitute:
)
Therefore, the value of is
satisified the equation.
The value of is
.