$\"\"$ $\"\"$ $\"\"$

\

The original function is $\"\"$

\

Write $\"\"$ as $\"\"$ or $\"\"$ $\"\"$

\

First solve the case $\"\"$ .

\

$\"\"$ (Subtract 2 from each side)

\

$\"\"$ (Additive inerse property: $\"\"$ )

\

$\"\"$ $\"\"$ $\"\"$ (Additive identity property: $\"\"$ $\"\"$ )

\

$\"\"$ $\"\"$ (Subtract: $\"\"$ )

\

Apply Division proparty of inequality: If a = b than $\"\"$

\

$\"\"$ $\"\"$ (Divide each side by4)

\

$\"\"$ $\"\"$ (Cancel commen terms)

\

$\"\"$ $\"\"$ (Divide: $\"\"$ $\"\"$ $\"\"$ $\"\"$ v) $\"\"$

\

Next solve the case $\"\"$ .

\

$\"\"$ (Subtract 2 from each side)

\

$\"\"$ (Additive inerse property: $\"\"$ )

\

$\"\"$ (Additive identity property: $\"\"$ )

\

$\"\"$ $\"\"$ $\"\"$ (Subtract: $\"\"$ )

\

Apply Division proparty of inequality: If a = b than $\"\"$

\

$\"\"$ (Divide each side by 4)

\

$\"\"$ $\"\"$ (Cancel commen terms)

\

$\"\"$ (Divide: $\"\"$ $\"\"$ $\"\"$ ) $\"\"$

\

To graph the solutions set, first draw a number line.

\

Draw a heavy line between -2 and 3. Since -2 and 3 are not included in the solution set draw a circle at --2 and 3.

\

$\"absolute$

\

$\"\"$

\

The solution set is $\"\"$ .