Vince is correct.
Because Grady neglected to multiply by the negative sign.
The coefficient in is negative .
Therefore, the graph of the function must be reflected in the –axis.
![\"\"](\"/userfiles/image/steps_images/step1.JPG\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=52257f1605fb2b790995dd69987af2c6.png\")
in ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=ad56b5eb1a337bdf8298088e524dfe20.png\")
is negative ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=147603b341f0424c724cd8a59d5d22fe.png\")
.![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=c47a7e04a20a2071994f747c7de6fa0a.png\")
must be reflected in the ![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=8da2268e35b6b6daab9c47f71c4c8bf4.png\")
–axis.![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")