The inequality is .
Step 1:
\The exclude value for this inequality is and
.
Step 2:
\Solve the related equation.
\ (Original equation)
The LCD for the term is .
Multiply by LCD.
\ (Divide common factors)
(Multiply)
(Combine like terms)
(Subtract
from each side)
(Additive imverse property:
)
(Factors)
and
(Simplify)
Step 3:
\Draw vertical line at the excluded value and at the solutions to separate the number line into intervals.
\Graph:
\Graph the number line.
\Step 4: Test values are in each interval to determine the values of interval satisfy the inequality.
\Case (i):
\Test .
(Original inequality)
(Substitute
)
(Simplify)
(LCD is
)
(Subtract the numerator)
(Simplify)
Case (ii):
\ Test .
(Original inequality)
(Substitute
)
(Simplify)
(LCD is
)
(Subtract the numerator)
(Simplify)
Case (iii): Test .
(Original inequality)
(Substitute
)
(Simplify)
(Simplify)
Case (iv):
\Test .
(Original inequality)
(Substitute
)
(Simplify)
(Simplify)
(Addition)
Case (v):
\Test .
(Original inequality)
(Substitute
)
(Simplify)
(LCD is
)
(Addition)
(Simplify)
The statement is true for and
.
Therefore the solution is or
.
The solution is or
.