$\"\"$ $\"\"$

\

The given line is $\"\"$ .

\

above line is slope - intercept form $\"\"$ .

\

So, given line has a slope of( $\"\"$ ) = 3.

\

So, a line parallel to it has a slope of $\"\"$ .

\

Because you know the slope and a point on the line,

\

Use point - slope form $\"\"$ to write an equation of the line.

\

Let $\"\"$ = $\"\"$ and slope( $\"\"$ ) = 3.

\

$\"\"$ (Substitute 8 for $\"\"$ , 2 for $\"\"$ and $\"\"$ = 3) $\"\"$

\

Rewrite in slope - intercept form $\"\"$ .

\

$\"\"$ (Product of two same signs is positive)

\

$\"\"$ (Apply distributive property: $\"\"$ )

\

$\"\"$ (Multiply: $\"\"$ ) $\"\"$

\

$\"\"$ (Add 8 to each side)

\

$\"\"$ (Apply additive inverse property: $\"\"$ )

\

$\"\"$ (Apply additive identity property: $\"\"$ )

\

$\"\"$ (Add: $\"\"$ ) $\"\"$

\

Substitute $\"\"$ = $\"\"$ in equation $\"\"$ .

\

$\"\"$

\

$\"\"$ (Multiply: $\"\"$ )

\

$\"\"$ (Subtract: $\"\"$ )

\

The equation satisfies the condition.

\

So,The equation of the line is $\"\"$ . $\"\"$

\

The equation of the line is $\"\"$ .