From the diagram, the opposite side of is EF and hypotenuse is DF.
(Definition of sine ratio) \ \
So to find , we use the side lengths of EF and DF. \ \
We use the side lengths of EF and DF to find .
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/step1.JPG\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=524f740941b8a3b94221191ed92451e7.png\")
is EF and hypotenuse is DF.![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=1adca0eb307f07ac818060be941c0986.png\")
(Definition of sine ratio) \ \
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=ad6e393414fc5742a0a1dc2b63a4facb.png\")
, we use the side lengths of EF and DF. \ \
![\"\"](\"http://www.mathskey.com/userfiles/image/steps_images/solution.JPG\")
![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=ad6e393414fc5742a0a1dc2b63a4facb.png\")
.