$\"\"$

The equation is $\"\"$ .

The equation in slope-intercept form y = mx + c. $\"\"$

Make a table; choose some values for x and find the corresponding values for y. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\
x
\ \
y = 2 x - 5
\ \
y
\ \
(x, y)
\
\
- 2
\ \
Y = 2(-2) - 5 = -9
\ \
-9
\ \
(-2, -9)
\
\
-1
\ \
Y = 2(-1) - 5 = -7
\ \
-7
\ \
(-1, -7)
\
\
0
\ \
Y = 2(0) - 5 = -5
\ \
-5
\ \
(0, -5)
\
\
1
\ \
Y = 2(1) - 5 = -3
\ \
-3
\ \
(1, -3)
\
\
2
\ \
Y = 2(2) - 5 = -1
\ \
-1
\ \
(2, -1)
\
\

$\"\"$

Use these ordered pairs to graph the equation.

1. Draw a coordinate plane.

2. Plot the points.

3. Draw a line through these points.

$\"graph$

\ x \	\ *y =* 2 x - 5 \	\ y \	\ *(x, y)* \
\ - 2 \	\ Y = 2(-2) - 5 = -9 \	\ -9 \	\ (-2, -9) \
\ -1 \	\ Y = 2(-1) - 5 = -7 \	\ -7 \	\ (-1, -7) \
\ 0 \	\ Y = 2(0) - 5 = -5 \	\ -5 \	\ (0, -5) \
\ 1 \	\ Y = 2(1) - 5 = -3 \	\ -3 \	\ (1, -3) \
\ 2 \	\ Y = 2(2) - 5 = -1 \	\ -1 \	\ (2, -1) \