
The line equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
\Write the two functions as co-ordinates.
\

First find the slope
\
 (Substitute
                 (Substitute  )
)
 (Subtract: 4 – 1 = 3 and 6 – 3 = 3)
                       (Subtract: 4 – 1 = 3 and 6 – 3 = 3)
m = 1                          (Cancel common terms)
Next find the y-intercept
\Substitute the slope and the coordinates of the given point  in slope-intercept form equation.
 in slope-intercept form equation.
y = mx + b
\1 = 1(3) + b (Substitute 1 for m, 3 for x, and 1 for y)
\1 = 3 + b                     (Apply multiplicative identity property:  )
)
1 – 3 = 3 – 3 + b (Subtract 3 from each side)
\1 – 3 = b (Apply additive inverse property: 3 – 3 = 0)
\b = – 2                        (Subtract: 1 – 3 = – 2)
Finally write the line equation
\Substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept form line equation.
\y = mx + b
\y = (1)(x) + (– 2) (Substitute 1 for m and – 2 for b)
\y = x – 2                        (Product of two different signs is negative)
The function is y = x – 2.