$\"\"$

The equation is $\"\"$ .

The equation in slope-intercept form y = mx + c. $\"\"$

Make a table; choose some values for x and find the corresponding values for y. \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\
x
\ \
y = - x + 1
\ \
y
\ \
(x, y)
\
\
- 2
\ \
Y = -(-2) + 1 = 3
\ \
3
\ \
(-2, 3)
\
\
-1
\ \
Y = -(-1) + 1 = 2
\ \
2
\ \
(-1, 2)
\
\
0
\ \
Y = 0 + 1 = 1
\ \
1
\ \
(0, 1)
\
\
1
\ \
Y = -1 + 1 = 0
\ \
0
\ \
(1, 0)
\
\
2
\ \
Y = -2 + 1 = -1
\ \
-1
\ \
(2, -1)
\
\

$\"\"$

Use these ordered pairs to graph the equation.

1. Draw a coordinate plane.

2. Plot the points.

3. Draw a line through these points.

$\"graph$

\ x \	\ *y = - x +* 1 \	\ y \	\ *(x, y)* \
\ - 2 \	\ Y = -(-2) + 1 = 3 \	\ 3 \	\ (-2, 3) \
\ -1 \	\ Y = -(-1) + 1 = 2 \	\ 2 \	\ (-1, 2) \
\ 0 \	\ Y = 0 + 1 = 1 \	\ 1 \	\ (0, 1) \
\ 1 \	\ Y = -1 + 1 = 0 \	\ 0 \	\ (1, 0) \
\ 2 \	\ Y = -2 + 1 = -1 \	\ -1 \	\ (2, -1) \