The line equation in slope-intercept form is y = mx + b, where m is the slope and b
\is the y-intercept.
\First find the slope
\m =
= (Substitute
)
= (Product of two same signs is positive)
= (Add:
)
= (Additive identity property:
)
= 2 (Divide: )
Next find the y-intercept
\Substitute the slope and the coordinates of the given point in slope-intercept form
\line equation.
\y = mx + b
\ (Substitute 2 for m, –2 for x, and 8 for y)
(Multiply:
)
(Add 4 to each side)
(Commutative property of addition: a + b = b + a)
(Additive inverse property:
)
b =12 (Add: 8 + 4 = 12)
Finally write the equation of the line
\Substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept form
\y = mx + b
\ (Substitute 2 for m and 12 for b)
(Simplify)
The equation of the line that passes through the point (–2, 8) and (–6, 0) is
\.