The line equation in slope-intercept form is y = mx + b, where m is the slope
\and b is the y-intercept.
\Identify the slope. The slope is –5.
Find the y-intercept value by substituting the slope and the coordinates of the
\given point in the equation.
\y = mx + b (Slope-intercept form line equation)
\ (Substitute –5 for m, –4 for x, and 7 for y)
(Multiply:
)
(Subtract 20 from each side)
(Apply commutative property of addition: a + b = b + a)
(Apply additive inverse property: 20 – 20 = 0)
(Subtract:
)
Now substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept
\form line equation.
\y = mx + b (Slope-intercept form line equation)
\ (Substitute –5 for m and –13 for b)
(Product of two different signs is negative)
The Equation of the line that passes through the point (–4, 7) and has
\a slope of –5 is .