The line equation in slope-intercept form is y = mx + b, where m is the slope
\and b is the y-intercept.
\Identify the slope. The slope is –2.
Find the y-intercept value by substituting the slope and the coordinates of the
\given point in the equation.
\y = mx + b (Slope-intercept form line equation)
\ (Substitute –2 for m, 5for x, and -5 for y)
(Multiply:
)
(Add 10 to each side)
(Apply commutative property of addition: a + b = b + a)
(Apply additive inverse property:
)
(Add:
)
Now substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept
\form line equation.
\y = mx + b (Slope-intercept form line equation)
\ (Substitute –2 for m and 5 for b)
(Product of two different signs is negative)
The equation of the line that passes through the point (5, 1) and has
\a slope of –2 is .