\
\
The line equation in slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.
\Write the two functions as co-ordinates.
\First find the slope
\ (Substitute
)
(Product of two same signs is positive)
(Subtract:
)
(Add: 2 + 1 = 3)
(Divide:
)
Next find the y-intercept
\ \Substitute the slope and the coordinates of the given point in slope-intercept form equation.
y = mx + b
\15 = –2(–2) + b (Substitute – 2 for m, – 2 for x, and 15 for y)
\15 = 4 + b (Multiply: )
15 – 4 = 4 – 4 + b (Subtract 4 from each side)
\15 – 4 = b (Apply additive inverse property: 4 – 4= 0)
\b = 11 (Subtract: 15 – 4 = 11)
Finally write the line equation
\Substitute the values of slope ‘m’ and y-intercept ‘b’ in slope intercept form line equation.
\y = mx + b
\y = –2(x) + 11 (Substitute –2 for m and 11 for b)
\y = –2x + 11 (Simplify)
The function is y = –2x + 11.