Given equations are
\Multiply equation 1 with 3 and equation 2 with 5
\Add multiplied equations 1 and 2
\7y +28 = 0
\Therefore 7y = -28 ==> y = -28/7==> y = -4
\Substitute y = -4 in equation 2
\3x + 4(-4) -2 =0===>3x - 16 - 2 = 0
\= 3x -18 = 0==>3x = 18==> x = 18/3 ==>x = 6
\Therefore the solutions for the given equation 1 and 2 is x = 6 and y = -4