Given equations are

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Multiply equation 1 with 3 and equation 2 with 5

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Add multiplied equations 1 and 2

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7y +28 = 0

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Therefore 7y = -28 ==> y = -28/7==> y = -4

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Substitute y = -4 in equation 2

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3x + 4(-4) -2 =0===>3x - 16 - 2 = 0

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= 3x -18 = 0==>3x = 18==> x = 18/3 ==>x = 6

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Therefore the solutions for the given equation 1 and 2 is x = 6 and y = -4