Given that
\Substitute the value of x=1
\f(1) = 0
\That means (x-1) is a factor for the given equation
\Take 3 common
\ \ \
3 is also a factor
Take (x+3) common
\The remaining factors are (x+2) (x+3)
\The factors the given polynomial is (x-1) (x+2) (x+3)
\Therefore the roots of the given polynomial is (x-1) = 0 ==> x = 1
\(x+2) =0 ==> x = -2
\(x+3) = 0 ==> x = -3
\The sum of the roots are 1 - 2 - 3 = -4
\