Elimination method :
\The system of equations are
\ → ( 1 )
→ ( 2 )
→ ( 3 )
Change the equations from fraction form to linear equation.
\The L.C.M of 3,4, and 8 in eq (1) is 24, so multiply eq (1) by 24.
\ → ( 4 )
The L.C.M of 5,3, and 4 in eq (2) is 60, so multiply eq (2) by 60.
\ → ( 5 )
The L.C.M of 5,3, and 8 in eq (3) is 120, so multiply eq (3) by 120.
\ → ( 6 )
Write the eqn\\'s (4) & (5) in column form and add the equations to eliminate z - variable.
\The resultant equation is → ( 7 )
To get the eq\\'ns (5) & (6) that contain opposite terms multiply the eq (5) by 7.
\Write the equations in column form and subtract the equations to eliminate z - variable.
\\
The resultant equation is → ( 8 )
To get the eq\\'ns (7) & (8) that contain opposite terms multiply the eq (7) by 13 and eq (8) by 14.
\Write the equations in column form and subtract the equations to eliminate x - variable.
\\
The resultant equation is .
Substitute the value of in eq (7), and solve for x.
Substitute the values of and
in eq (4), and solve for z.
.
Therefore, solution of the given system is .
\
\