Elimination method :

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The system of equations are

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\"\"         → ( 1 )

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\"\"      → ( 2 )

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\"\"  → ( 3 )

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Change the equations from fraction form to linear equation.

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The L.C.M of 3,4, and 8 in eq (1) is 24, so multiply eq (1) by 24.

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\"\"                    ( 4 )

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The L.C.M of 5,3, and 4 in eq (2) is 60, so multiply eq (2) by 60.

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\"\"         → ( 5 )

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The L.C.M of 5,3, and 8 in eq (3) is 120, so multiply eq (3) by 120.

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\"\" ( 6 )

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Write the eqn\\'s (4) & (5) in column form and add the equations to eliminate z - variable.

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\"\"

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The resultant equation is \"\" ( 7 )

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To get the eq\\'ns (5) & (6) that contain opposite terms multiply the eq (5) by 7.

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Write the equations in column form and subtract the equations to eliminate z - variable.

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\"\"

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The resultant equation is \"\" ( 8 )

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To get the eq\\'ns (7) & (8) that contain opposite terms multiply the eq (7) by 13 and eq (8) by 14.

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Write the equations in column form and subtract the equations to eliminate x - variable.

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\"\"

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The resultant equation is \"\".

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Substitute the value of \"\" in eq (7), and solve for x.

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\"\"

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Substitute the values of \"\" and \"\" in eq (4), and solve for z.

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\"\"

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\"\".

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Therefore, solution of the given system is \"\".

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