The curve is , and the point is .

We can use implicit differentiation to find y \\'.

The implicit(or total) derivation of is,

.

Substitute the values of (x, y ) = (0, 1) in the above equation.

.

This is the slope (m ) of the tangent line to the implicit curve at (0, 1).

To find the tangent line equation, substitute the values of and (x, y ) = (0, 1) in the slope intercept form of an equation.

y = mx + b.

1 = (1 / 2)(0) + b

b = 1. \ \

Substitute and b in y = mx + b.

y = (1 / 2)x + 1.

The tangent line equation is .