The curve is \"\", and the point is (2, 0).

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We can use implicit differentiation to find y \\'.

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The implicit(or total) derivation of \"\" is, \ \

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\"\"

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Substitute the values of (x, y ) = (2, 0) in the above equation.

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\"\"

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\"\"

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\"\".

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This is the slope (m ) of the tangent line to the implicit curve at (2, 0).

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To find the tangent line equation, substitute the values of \"\" and (x, y ) = (2,0) in the slope intercept form of an equation.

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y = mx + b

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\"\"

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\"\".

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Substitute \"\" and \"\" in y = mx + b.

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\"\"

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\"\".

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The tangent line equation is \"\".