Given that

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\"\"

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\"\"

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We have formula that

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\"\"

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\"\"

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\"\"

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\"\"

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Take (x+3) common

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\"\"

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Cancel (x+3) from numerator and denominator

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\"\"

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Substitute the value of x is -3

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\"\"

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\"\"

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 Divide by 2 and also cancel negitive symbol

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\"\"

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Therefore the value of t6he givewn limit is  \"\"