4) The inequality is
State the exclude values,These are the values for which denominator is zero.
\The exclude value of the inequality is 8,30.
\Solve the related equation
Solution of related equation x = -11.
\Draw the vertical lines at the exclude values and at the solution to separate the number line into intervals.
\Now test sample values in each interval to determine whether values in the interval satisify the inequality.
\Test interval x - value Inequality Conclusion
\(-∞, -11) x = -20 True
(-11, 8) x = 0 False
(8, 30) x = 10 True
(30, ∞) x = 35 False
The above conclude that the inequality is satisfied for all x - values in (-∞, -11) and (8, 30).
\This implies that the solution of the inequalityis the interval (-∞, -11) and (8, 30) . as shown in Figure below. Note that the original inequality contains a “≤ ” symbol. This means that the solution set contain the endpoints of the test intervals are (-∞, 0) and(1/2, ∞)
\ \ .