(1)

Given polynomial 

Step 1 :   Rational roots test -Finding real factor

Substitute 1,-1  in f(x)

Substitute 2,-2  in f(x)

So ( x-2 ) is one solution.

x = 2

Step 2 :   Synthetic division - Reducing the order

Now equation is re written as

Since (x-2) is root si taken as commen.Then remaining part is formed by using

remained below coefficients of above table.

Step 3 :

Find roots of equation

Compare the equation with general form of quadratic equation ax² + bx + c = 0.

a = 1 , b = -7 and c = 12.

Substitute a = 1 , b = -7 and c = 12 in the quadratic formula :

Step 4 :

Solution is x = 2 , 3 ,4

(2)

Given polynomial  

Step 1 :   Rational roots test -Finding real factor

Substitute 1,-1  in f(x)

Substitute 2,-2  in f(x)

So ( x-2 ) is one solution.

x = 2

Step 2 :   Synthetic division - Reducing the order

Now equation is re written as

Since (x-2) is root si taken as commen.Then remaining part is formed by using

remained below coefficients of above table.

Step 3 :

Find roots of equation

Compare the equation with general form of quadratic equation ax² + bx + c = 0.

a = 1 , b = -7 and c = 12.

Substitute a = 1 , b = -7 and c = 12 in the quadratic formula :

Step 4 :

Solution is x = 2 , 3 ,4

Given polynomial