Cost function C(x) = 3500 + 10x \ \

\

Demand ( Price ) function p(x) = 40 - (1/1500)x \ \

\

Revenue equation r(x) = Price function * Number of units \ \

\

\"\" \ \

\

\"\" \ \

\

\"\"

\

Profit equation = Profit function s(x) = Revenue function - Cost Function

\

s(x) = r(x) - c(x) \ \

\

\"\"

\

\"\"

\

\"\"

\

To calculate profit \ \

\

Substitute x = 2250 \ \

\

Profit at x=2250 \"\"

\

\"\"

\

\"\"

\

Marginal profit :

\

\

Marginal profit is the derivative (slope )of the profit function. \ \

\

so take the derivative of p(x) and evaluate it at x = 2250

\

\

\"\"

\

Apply derivative \ \

\

\"\"

\

\"\"

\

\"\"

\

Substitute x = 2250

\

\"\"

\

\"\"

\

Solution :

\

Revenue equation \"\"

\

Profit at 2250 units is  \"\"

\

The marginal profit when 2250 units are produced is 48490 dollars