Cost function C(x) = 3500 + 10x \ \
\Demand ( Price ) function p(x) = 40 - (1/1500)x \ \
\Revenue equation r(x) = Price function * Number of units \ \
\ \ \
\ \
Profit equation = Profit function s(x) = Revenue function - Cost Function
\s(x) = r(x) - c(x) \ \
\To calculate profit \ \
\Substitute x = 2250 \ \
\Profit at x=2250
Marginal profit :
\\
Marginal profit is the derivative (slope )of the profit function. \ \
\so take the derivative of p(x) and evaluate it at x = 2250
\ \Apply derivative \ \
\Substitute x = 2250
\Solution :
\Revenue equation
Profit at 2250 units is
The marginal profit when 2250 units are produced is 48490 dollars