(5)
\Given points
\( x1 , y1 ) = ( 4 , -4 )
\( x2 , y₂ ) = ( 8 , -10 )
\Slope
Substitute x1 = 4 , y1 = -4 , x2 = 8 , y2 = -10 \ \
\Formula for Slope point form : ( y - y1 ) = m ( x - x1 )
\Substitute x1 = 4 , y1 = -4 and
( y - (-4) ) = ( x - 4 )
2 ( y + 4 ) = ( - 3 )( x - 4 )
\2y + 8 = -3x + 12
\3x - 12 + 2y + 8 = 0
\3x + 2y - 4 = 0
\Solution :
\3x + 2y - 4 = 0
\