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(c) \ \

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The vertex form of a quadratic equation is y = a(x - p)² + q \ \ where (p, q) are the x- and y-coordinates of the vertex

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vertex is (0,2) and passes through the point (-3,11) \ \

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vertex (0, 2) is lies on parabola.So substitute p = 0 , q = 2 \ \ y = a(x - 0)² + 2 \ \

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y = ax² + 2 \ \ passes through the point (-3,11) \ \ 11 = a(-3)² + 2 \ \

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11 - 2 = 9a \ \

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a = 9/9 \ \ a = 1 \ \ Therefore, the quadratic equation is: \ \

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y = (1)(x + 0)² + 2 \ \

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y = x² + 2 \ \

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