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Given equation : y - 5 = -2(x+1)²

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Apply Square of a Binomial: (u + v)² = u² + 2uv + v².

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y - 5 = -2(x²+1²+2(x)(1))

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y - 5 = -2(x²+1+2x)

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y - 5 = -2x² - 2 - 4x

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Add 5 to each side. \ \ y  = -2x² - 2 - 4x + 5

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y  = -2x² - 4x + 3

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The standard form of vertex form of quadratic function is y  = -2x² - 4x + 3

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