Length of rectangle = a
\Width of rectangle = b
\Rectangle area = ab = 221 m²
\b = 221/a
\Rectangle peremeter = 2(a+b) = 60 m
\(a+b) = 30
\Substitute a = 221/b
\(a+(221/a)) = 30
\a²+221 = 30a
\a² - 30a + 221 = 0
\a² - 13a - 17a+ 221 = 0
\a ( a - 13 ) - 17 ( a - 13 ) = 0
\( a - 13 ) ( a - 17 ) = 0
\( a - 13 ) = 0 and ( a - 17 ) = 0
\a = 13 and a = 17
\If a = 13 then b = 221/13 = 17
\(Length is greater than width.So it is false result.)
\If a = 17 then b = 221/17 = 13
\(Length is greater than width.So it is TRUE result.)
\Solution :
\Length of rectangle = 17m
\Width of rectangle = 13m