1.2.2)

Given data :

fired angle θ = 29°

initial velocity v₀ =  410 m/s

Earth gravity g = 9.8 m/s

The horizontal displacement reached by the bullet d = ?

Formula :

Horizontal displacementd = (v₀²sin2θ)/g

Substitute : v₀ =  410 m/s , θ = 29° and  g = 9.8 m/s.

d = (410²sin(2×29)) / (9.8)

d = (410²(0.848)) / (9.8)

d = 14546.62 m

The horizontal displacement is 14546.62 meters