2.2) \ \

Given data

Diameter d = 500 mm \ \

1 mm = (10^-3) m \ \

d = 500×10^-3 m \ \

d = 0.5 m \ \

Velocity v = 200 km/h \ \

1km/h = (5/18) m/s \ \

v = 200 (5/18) m/s \ \

v = 55.56 m/s \ \

2.2.1) \ \

revolutions per minute (rev/min) = ? \ \

The number of circumferences of wheel which fit inside the total distance is the number of times the wheel revolves( rev/min) in that time period. \ \

The number of revolutions per minute = (speed) / (circumference of wheel) \ \

The number of revolutions per minute = v / πd \ \

= 55.56 / 0.5π \ \

= 35.3857 \ \

= 35 rpm \ \

rpm = The revolutions per minute \ \

The number of revolutions of wheel per minute is 35 \ \