2.2.2)
\Given data
\Diameter d = 500 mm
\1 mm = (10-3) m
\d = 500×10-3 m
\d = 0.5 m
\radius r = d/2
\r = 0.5/2
\r = 0.25 m
\linear speed v = 200 km/h
\1km/h = (5/18) m/s
\v = 200 (5/18) m/s
\v = 55.56 m/s
\Angular velocity ω = ?
\The angular velocity is defined as the rate of change of angular displacement.
\The number of revolutions per minute = (speed) / (circumference of wheel)
\The number of revolutions per minute (rpm) = v / πd
\= 55.56 / 0.5π
\= 35.3857 rpm
\Angular velocity ω= rpm x (2π)/60
\ω = 35.387 x (2π)/60
\ω = 35.387 x (2π)/60
\ω = 3.70 rad/s
\Solution :
\The angular velocity of wheel is 3.7 rad/s
\