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(5.3.2)

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Consider Single - acting pump

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Number of Cylinders n = 3

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Piston diameter d = 12 cm

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d = 12/100 m = 0.12 m

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Stroke length s = 50 m

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s = 50/100 = 0.5 m

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Slip = 13% = 0.13

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Speed N = 350 RPM

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Cross sectional area of piston A = (¼)πd²

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A = (¼)π(0.12)²

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A = 0.0113 m²

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Volume of Water discharge Q = (A×s×n×N)/231

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Q = (0.0113×0.5×3×350)/231

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Q = 0.0257 Gallons per minute

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But due to slip 13% is lost.So

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Q = 0.0257× 0.13 Gallons per minute

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Q = 0.003341 Gallons per minute

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1 Gallons per minute = 3.78541 litres/minute.

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Q = 3.78541×0.003341

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Q = 0.01264 litres/minute.

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The volume of water delivered is 0.01264 litres/minute.

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