3.1.1 )
\Bar diameter db = 50 mm
\dr = 50/1000 = 0.05 m
\r = d/2 = 0.05/2 = 0.025 m
\Torque required to overcome friction of the lathe spindle Tf = 12 N-m
\Tangential force F = 2400 N
\Torque T = rF
\T = (0.025)(2400)
\T = 60 N-m
\Torque required at the driving pulley on the machine is 60 N-m
\