3.2.3)
\Maximum input Pmax = 2.5 kW
\Speed N = 1500 rpm
\At maximum power the machine efficiency η = 85 %
\Maximum Speed Nmax = 3500 rpm
\Minimum Speed Nmin= 30 rpm
\The torque at the driving spindle of the lathe at minimum speed T = ?
\P = 2πNT/60
\At spindle power losses included.So 85 % of total power is remained.
\Power at spindle Ps = ηPmax
\Ps = 0.85×2.5×103
\Ps = 2125 W
\But at minimum speed , torque is maximum.So T = Tmax
\Ps = 2πNminTmax/60
\Tmax = Ps×60/(2πNmin)
\Substitute Nmin = 30 , Ps = 2125
\Tmax = 2125×60/(2π×30)
\Tmax = 795.775 N-m
\The torque at the driving spindle of the lathe at minimum speed is 795.775 N-m
\