Rewrite the expression in long division form (6x3 - x2 - 10)/(3x + 4).
\Because there is no x - term in the dividend, we need to line up the subtraction by using zero coefficients (or leaving spaces) for the missing terms.
\Divide the first term of the dividend by the first term of the divisor 6x3/3x = 2x2.
\So,the first term of the quotient is 2x2. Multiply (3x + 4) by 2x2 and subtract.
\Divide the first term of the last row by first term of the divisor -9x2/3x = -3x.
\So,the second term of the quotient is (-3x). Multiply (3x + 4) by (-3x) and subtract.
\Divide the first term of the last row by first term of the divisor 12x/3x = 4.
\So,the third term of the quotient is 4. Multiply (3x + 4) by 4 and subtract.
\Quotient Q(x) = 2x2 - 3x + 4.
\Remainder R(x) = - 26.