Given
\a=13
\b=26
\For any right triangled,One angle is equals to 90º.
\In given problem we need to find angles A,B (unknown angles).
\So C should be known.So consider C = 90º.
\For a right triangle ABC
\c² = a² + b²
\c² = 12² + 26²
\c² = 820
\c = 28.64
\sinB = b/c
\sinB = 26/28.64
\B = sin-1(0.9078)
\B = 65.2º
\Total of all angles in a triangle is 180º
\A + B + C =180
\A = 180 - B - C
\A = 180 - 65.2 - 90
\A = 24.8º
\Solution :
\Side length c =28.64
\Angles B = 65.2º and A = 24.8º
\