Mass of astronaut m = 83 kg
\Distance from the center of the Earth\\'s Moon r = 2500 km
\r = 2500000 m
\Acceleration a = 2 m/s²
\Apparent weight Wnet = ?
\Assuming that the Earth, astronaut, and Moon are momentarily all in perfect alignment.
\Net force Fg = G[m1m2] / r^2
\G = gravitational constant (6.673E-11)
\m1 = mass of object one in kg (the Moon)
\m2 = mass of object two in kg (the astronaut)
\r = distance from the center-to-center of the two objects in meters
\G = 6.67428×10-11 m^3/kg-s^2
\m1 = 83 kg
\m2 = 7.3477×1022 kg
\r = 2500000
\Fg = (6.67428×10-11)(83)(7.3477×1022) / (2500000)²
\Fg = 65.126 N
\Gravitional acceleration due to moon gmoon = Gm1/r²
\gmoon = (6.67428×10-11)(7.3477×1022) / (2500000)²
\gmoon = 0.784 m/s²
\The astronaut is accelerating towards moon so net acceleration gr = 2 - 0.784 - 2 = 1.216 m/s²
\Apparent weight Wnet = Fg + mgr
\Wnet = 65.126 + 83*1.216
\Wnet = 65.126 + 100.928
\Wnet = 166.054 N