From given figure

Resistance values R₁ = 10 kΩ , R₂ = 10 kΩ , R₃ = 22 kΩ , R₄ = 33 kΩ

Step 1 :

Resistors R₃ = 22 kΩ , R₄ = 33 kΩ are in parallel.

Equivalent resistance R₅ = R₃ // R₄

R₅ =  (R₃R₄) / [R₃+R₄]

R₅ =  (22000*33000) / [22000+33000]

R₅ =  (726000000) / 55000

R₅ =  13200

R₅ =  13.2 kΩ

Step 2 :

Resistors R₅ = 13.2 kΩ , R₂ = 10 kΩ are in seires.

Equivalent resistance R₆ = R₅ + R₂

R₆ = 13.2 k + 10 k

R₆ = 14.2 kΩ

Step 3 :

Resistors R₆ = 14.2 kΩ , R₁ = 10 kΩ are in parallel.

Equivalent resistance R₇ = R₆ // R₁

R₇ =  (R₆R₁) / [R₆ + R₁]

R₇ =  (14.2k*10k) / [14.2k+10k]

R₇ =  (142*1000000) / 24.2 k

R₇ =  5.87 kΩ

Solution :

Total resistance of the circuit is 5.87 kΩ