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The curve equation is y = 3x3/2 - 1 and the interval is [0, 3].

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The arc length of f(x) between a and b is \"image\"

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y = (1/3)(x2+2)3/2 ⇒ y\\' = (1/3)(3/2)(2x)(x2+2)1/2 ⇒ y\\' = x(x2+2)1/2.

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Substitute y\\' = x(x2+2)1/2, a = 0 and b = 3 in the above formula.

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