Step 1:

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The function is  \"\".

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Change \"\" to \"\".

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\"\"

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Obtain the graph of  \"\"from basic function \"\" ,subtract \"\" from each \"\"-coordinate on graph of basic function.

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\"\" graph by using basic function \"\"

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Choose random values for \"\" and find the corresponding values for \"\".

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\"\"\"\"\"\"
\"\"\"\"\"\"
\"\"\"\"\"\"
\"\"\"\"\"\"
\"\"\"\"\"\"
\"\"\"\"\"\"
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Step 2:

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Graph

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 Draw the the coordinate plane.

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Plot the points of the basic function  \"\" and  \"\".

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Connect these points with smooth curve.

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Plot the points of the \"\" are  \"\" and \"\"

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Connect these points with smooth curve.

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.

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The graph of \"\" is identical to \"\" except that it is vertically shifted down 1 unit.

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Step 3:

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The domain of the \"\" is all real numbers.

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Domain  of f in the interval notation: \"\".

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Range of  \"\" is \"\"

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Range  of f in the interval notation: \"\".

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Solution:

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Domain  of f in the interval notation: \"\".

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Range  of f in the interval notation: \"\".

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contd...

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Graph:

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.

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The graph of \"image\" is identical to \"image\" except that it is vertically shifted down 1 unit.

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Step 3:

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The domain of the \"image\" is all real numbers.

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Domain of f  in the interval notation: \"image\".

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Range of  \"image\" is \"image\"

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Range  of f in the interval notation: \"image\".

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Solution:

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Domain  of f in the interval notation: \"image\".

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Range  of f in the interval notation: \"image\".