Step 1 :

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(a)

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The height of the rock after t seconds is \"\".

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Velocity at the surface of the Mars \"\".

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Velocity is derivative of displacement function.

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Differentiate h with respect to t.

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\"\"

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Velocity of rock after t seconds is \"\".

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Velocity of rock after 2 seconds:

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\"\"

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Velocity of rock after 2 seconds is 7.56 m/s.

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Step 2 :

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(b)

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The height is 25 m.

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Height of the rock is \"\".

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\"\"

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Since roots of the quadratic function \"\" :

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\"\"Roots of the quadratic function \"\" :

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\"\"

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First root:

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\"\"

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Second root:

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\"\"

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Step 3 :

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Velocity at time \"\".

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\"\"

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At height 25 m. the velocity of rock on its way up is \"\".

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Velocity at time \"\".

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\"\"

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At height 25 m. the velocity of rock on its way down is \"\".

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Solution :

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(a) Velocity of rock after 2 seconds is 7.56 m/s.

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(b) The velocity of rock on its way up is \"\".

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     The velocity of rock on its way down is \"\".

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