Step 1 :
\(a)
\The height of the rock after t seconds is .
Velocity at the surface of the Mars .
Velocity is derivative of displacement function.
\Differentiate h with respect to t.
\Velocity of rock after t seconds is .
Velocity of rock after 2 seconds:
\Velocity of rock after 2 seconds is 7.56 m/s.
\Step 2 :
\(b)
\The height is 25 m.
\Height of the rock is .
Since roots of the quadratic function :
Roots of the quadratic function
:
First root:
\Second root:
\Step 3 :
\Velocity at time .
At height 25 m. the velocity of rock on its way up is .
Velocity at time .
At height 25 m. the velocity of rock on its way down is .
Solution :
\(a) Velocity of rock after 2 seconds is 7.56 m/s.
\(b) The velocity of rock on its way up is .
The velocity of rock on its way down is .
\