Step 1:

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Assume that he equation is \"\" has more than two real roots.

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Notice that polynomials are differentiable and  continuous over the reals.

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By Rolls theorem :

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If a function, \"\", is continuous on the closed interval \"\" , is differentiable on the open interval \"\" , and \"\", then there exists at least one number \"\", in the interval \"\" such that \"\".

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Consider \"\".

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\"\"

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The function \"\" has exactly one critical point, at \"\".

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Therefore, it is a decreasing function for \"\" and an increasing function for \"\".

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\"\"

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If \"\", then \"\" for all x, and hence it has no real roots.

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If \"\", then \"\" has a single real zero at \"\".

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If \"\", then \"\" Find x-values to the left and right of x = -1 where f > 0 and use the Intermediate Value Theorem to infer that f has two real roots. We\\'ve covered all possible cases for c, and we find that we never have more than two real roots.