Step 1 :

\

(a)

\

The height of the ball after t seconds is \"\".

\

Initial velocity of the ball at the surface of the Moon \"\".

\

The average velocity of ball at time t is \ \

\

\"\"

\

Velocity is derivative of displacement function.

\

Differentiate s(t) with respect to t.

\

\"\"

\

Velocity of ball after t seconds is \"\".

\

Velocity of ball after 2 seconds

\

\"\"

\

Velocity of ball after 2 seconds is 14.76 m/s.

\

Step 1 :

\

(a)

\

The height of the ball after t seconds is \"\".

\

Initial velocity of the ball at the surface of the Moon \"\".

\

The average velocity of ball at time t is \ \

\

\"\"

\

\"\"

\

The average velocity of ball at time 2 is \ \

\

\"\" \ \

\

So the average velocity formula at t = 2 is

\

\"\"

\

Step 2 :

\

(b)

\

The average velocity for the time interval beginning when t = 2 with duration 1 seconds .

\

Substitute \"\" in average velocity formula .

\

\"\"

\

 

\

The average velocity for the time interval beginning when t = 2 with duration 0.5 seconds .

\

Substitute \"\" in average velocity formula .

\

\"\"

\

The average velocity for the time interval beginning when t = 2 with duration 0.05 seconds .

\

Substitute \"\" in average velocity formula .

\

\"\"

\

Step 3 :

\

From the above calculations [ part (b) ] , one can estimate the instantaneous velocity at t = 2 .

\

When the duration of time decreases , the instantaneous velocity approaches to 14.7 m/s .

\

Check :

\

The instantaneous velocity at t = 2 is

\

\"\"

\

Solution :

\

(a) the average velocity formula at t = 2 is \"\".

\

(b) The average velocity when t = 2 with duration 1 seconds is \"\".

\

     The average velocity when t = 2 with duration 0.5 seconds is \"\".

\

     The average velocity when t = 2 with duration 0.5 seconds is \"\".

\

(c) The instantaneous velocity at t = 2 is \"\".

\

\

\