Step 1 :
\The acceleration due to gravity on earth is .
The velocity of the stone can be find , by integrating the acceleration.
\Apply integration on each side with t .
\The stone is freely falling , so the initial velocity of stone is 0 when t = 0.
Therefore velocity of a stone at time t is .
Step 2 :
\The velocity when it hits the ground is .
Find the time when it reaches the ground.
\Negative sign indicates that the stone is falling down.
\So the rock reaches the ground at time t = 3.73 sec.
\Step 3 :
\The position (height) of the stone can be find , by integrating the velocity.
\Apply integration on each side with t .
\When time t = 0 ,the height of stone is height of the cliff.
\ is the height of cliff.
When the stone reaches the ground the , the height of the stone is 0.
\Substitute t = 3.73 sec and .
The height of the cliff is 224 ft.
\Solution :
\The height of the cliff is 224 ft.
\\
\
\
\