Step 1 :

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The acceleration due to gravity on earth is \"\".

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The velocity of the stone can be find , by integrating the acceleration.

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\"\"

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Apply integration on each side with t .

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\"\"

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The stone is freely falling , so the initial velocity \"\" of stone is 0 when t = 0.

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\"\"

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Therefore velocity of a stone at time t is  \"\".

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Step 2 :

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The velocity when it hits the ground is \"\".

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Find the time when it reaches the ground.

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\"\"

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Negative sign indicates that the stone is falling down.

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So the rock reaches the ground at time t = 3.73 sec.

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Step 3 :

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The position (height) of the stone can be find , by integrating the velocity.

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\"\"

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Apply integration on each side with t .

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\"\"

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When time t = 0 ,the height of stone is height of the cliff.

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\"\"

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\"\"

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\"\" is the height of cliff.

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When the stone reaches the ground the , the height of the stone is 0.

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Substitute t = 3.73 sec and \"\".

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\"\"

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The height of the cliff is 224 ft.

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Solution :

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The height of the cliff is 224 ft.

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