\ \
\Step 1 :
\The function is
Domain of the function : \ \
\Since there should not be any negative numbers in the square root, \ \
\ \
The domain is .
Step 2 :
\Let
Apply derivative on each side with respect to x.
\Apply the product rule of derivative:
Step 3 :
\Determination of critical points:
\Since is a root function, it is continuous on its domain
.
The critical points exists when .
Equate to zero:
The critical points are
Consider the test intervals as and
. \ \
Interval | \Test Value | \Sign of ![]() | \
Conclusion | \
![]() | \
![]() | \
\
| \
Decreasing | \
![]() | \
![]() | \
\
| \
Increasing | \
![]() | \
![]() | \
\
| \
Decreasing | \
Thus, The function is increasing on the interval . \ \
And The function is decreasing on the intervals and
.
Solution :
\The function is increasing on the interval
. \ \
The function is decreasing on the intervals
and
.