Step 1:
\(a)
\The function is .
Find the critical numbers by equating the first derivative to .
Apply derivative on each side with respect to .
Equate the derivative to .
So the function has critical number at .
Solution :
\The function has critical number at .
Step 1:
\(b)
\The critical point is ,consider the table summarizes the testing of two intervals determined by the critical number.
Test interval | \![]() | \
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Test value | \ ![]() | \
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sign of ![]() | \
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Conclusion | \Increasing | \ \
Decreasing \ | \
So the function is increasing on the interval
and decreasing on the interval
.
Solution :
\The function is increasing on the interval
and decreasing on the interval
.
Step 1:
\(c)
\Use first Derivative Test to identify all relative extrema.
\The derivative of the function is .
The critical point is ,consider the table summarizes the testing of two intervals determined by the critical number.
Test interval | \![]() | \
![]() | \
Test value | \ ![]() | \
![]() | \
sign of ![]() | \
![]() | \
![]() | \
Conclusion | \Increasing | \ \
Decreasing \ | \
From the fist derivative test the function changing from positive to negative at
, then
has a relative maximum at
.
Find for .
So the function has relative maximum at
.
Solution :
\The function has relative maximum at
.
Step 1:
\(d)
\Graph the function is .
Now observe the graph :
\The function has critical number at .
The function is increasing on the interval
and decreasing on the interval
.
The function has relative maximum at
.
Solution :
\The function has critical number at .
The function is increasing on the interval
and decreasing on the interval
.
The function has relative maximum at
.
\
\
\