Step 1 :

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Thu function \"\"

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Domain :

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Thu function \"\"

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The function \"\" continuous for all the points except at \"\".

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Thus, the domain of the function \"\" is \"\".

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Intercepts :

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y - intercept is \"\":

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\"\"

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Thus, y - intercept is \"\".

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x - intercept :

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Consider \"\" and solve for x.

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\"\"

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Thus, x - intercept is \"\".

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Step 2 :

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Symmetry :

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If \"\", then the function \"\" is even and it is symmetric about x-axis.

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If \"\", then the function \"\" is odd and it is symmetric about origin.

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\"\"

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Here \"\"

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Thus, the function \"\" is neither even nor odd.

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Step 3 :

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Asymptotes :

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Vertical asymptote exist when denominator is zero.

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Equate denominator to zero.

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\"\"

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Vertical asymptote is \"\"

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Horizontal asymptote:

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The line \"\" is called a horizontal asymptote of the curve \"\" if either

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\"\" or \"\" 

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\"\"

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\"\"

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Thus, the horizontal asymptote is \"\"

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Step 4 :

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Intervals of increase or decrease :

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Differentiate \"\" with respect to x:

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\"\"

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\"\" is never zero.

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f is increasing on its domain because \"\"

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Step 5 :

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Determination of extrema :

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f is an increasing function, hence there is no chance of local minimum or maximum.

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Step 6 :

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Differentiate \"\" with respect to x:

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\"\"

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Determination of inflection point:

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\"\" is never zero.

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Hence, there is no inflection points.

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But at \"\" the function is undefined.

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Consider the test intervals as \"\" and \"\"

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Interval

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Test Value Sign of \"\"Concavity
\"\"\"\" \

\"\"

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Up
\"\" \"\" \

\"\"

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Down

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Thus, the graph is concave up on the interval \"\".

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The graph is concave down on the interval \"\".

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Step 7 :

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Graph of the function  \"\" :

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\"\"

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Solution :

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Graph of the function  \"\" :

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\"\"

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