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Step 1 :

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The function \"\".

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Rewrite the function as

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\"\"

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graph the function \"\".

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\"\"

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 Domain :

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 The function \"\"

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The function \"\" continuous for all the points except at \"\".

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The domain of the function \"\" is \"\".

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Intercepts :

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y - intercept is \"\":

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\"\"

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\"\"

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y - intercept is \"\".

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x - intercept :

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Consider \"\" and solve for x.

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\"\"

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x - intercept is \"\".

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Step 2 :

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Symmetry :

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If \"\", then the function \"\" is even and it is symmetric about x-axis.

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If \"\", then the function \"\" is odd and it is symmetric about origin.

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\"\"

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Here \"\"

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The function \"\" is neither even nor odd.

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Step 3 :

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Asymptotes :

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Vertical asymptote exist when denominator is zero.

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Equate denominator to zero.

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\"\"

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Vertical asymptote is \"\".

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Horizontal asymptote:

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The line \"\" is called a horizontal asymptote of the curve \"\" if either

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\"\" or \"\" 

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\"\"

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\"\"

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Thus, the horizontal asymptote is \"\".

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Step 4 :

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Intervals of increase or decrease :

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Differentiate \"\" with respect to x:

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\"\"

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\"\" is never zero in its domain.

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f is decreasing on its domain because \"\"

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Step 5 :

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Determination of extrema :

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f is an decreasing function, hence there are no relative extrema.

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Step 6 :

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Differentiate \"\" with respect to x:

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\"\"

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Determination of inflection point:

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\"\" is never zero on its domain.

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Hence, there is no inflection points.

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But at \"\" the function is undefined.

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Consider the test intervals as \"\" and \"\"

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Interval

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Test Value Sign of \"\"Concavity
\"\"\"\" \

\"\"

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Down
\"\" \"\" \

\"\"

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Up

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Thus, the graph is concave down on the interval \"\".

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The graph is concave down on the interval \"\".

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Step 7 :

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Graph of the function  \"\".

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Plot the intercept points \"\" and \"\"

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Draw the asymptotes \"\" and \"\".

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\"\"

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Solution :

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x - intercept is \"\" and y - intercept is \"\".

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The function does not have relative extreme.

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The function  does not have inflection points.

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The vertical asymptote is \"\" and  the horizontal asymptote is \"\".

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