(a)
\Step 1:
\Observe the graph : \ \
\As- coordinate approaches
,
- coordinate tends to
.
As- coordinate approaches
,
- coordinate tends to
.
The slope of the secant line using the two pints is .
Substitute and
in the slope equation.
Slope of the secant line is .
Solution:
\Slope of the secant line is .
\
(b)
\Step 1:
\Observe the graph : \ \
\As- coordinate approaches
,
- coordinate tends to
.
Consider another point from a graph with small change in.
As- coordinate approaches
,
- coordinate tends to
.
The slope of the tangent line using basic derivative form is .
Substitute and
in the slope equation.
Slope of the tangent line is .
The graph has horizontal tangent line at
.
Solution:
\Slope of the tangent line is .
\
(c)
\Step 1:
\Observe the graph : \ \
\The hallow circle in the graph indicates that , the point is not included in its domain.
\ is not included in the domain of
.
Therefore does not exist .
Solution:
\ does not exist.
\
(d)
\Step 1:
\Observe the graph : \ \
\We can observe from the graph that exists.
As approaches to
from the left side then
approaches to
approximately.
As approaches to
from the right side then
approaches to
approximately.
Since the left hand limit and right hand limit are equal, Limit exist.
\ \ \
Solution:
\.
\
\
(e)
\Step 1:
\Observe the graph : \ \
\ \ \
As approaches to
from the right side then
approaches to
approximately. \ \
Solution:
\.