.

\

\

Step 1:

\

The polynomial function is $\"\"$ .

\

The root of the function is $\"image\"$

\

Since the polynomial has only real coefficients, then must the conjugate be also a root.

\

Thus $\"image\"$ must also be a root of the polynomial.

\

$\"image\"$ .

\

$\"image\"$ is a one of the root of the function $\"image\"$ .

\

$\"\"$ .

\

Apply the long division method.

\

Divide the first term of the dividend by the first term of the divisor $\"\"$ .

\

So, the first term of the quotient is $\"\"$ . Multiply $\"\"$ by $\"\"$ and subtract.

\

$\"\"$

\

Divide the first term of the last row by first term of the divisor $\"\"$

\

So,the second term of the quotient is $\"\"$ Multiply $\"\"$ by $\"\"$ and subtract.

\

$\"\"$

\

Divide the first term of the last row by first term of the divisor $\"\"$

\

So,the second term of the quotient is $\"\"$ Multiply $\"\"$ by $\"\"$ and subtract.

\

$\"\"$

\

Quotient is $\"\"$

\

Remainder is $\"\"$

\

$\"\"$

\

$\"\"$

\

$\"\"$

\

The zeros of the functions are $\"\"$ .

\

Solution :

\

\

\