Step 1:  

\

(a)

\

The functions are \"\" and \"\" and the point is \"\".

\

Substitute the point \"\" in \"\".

\

\"\"

\

The slope of the tangent line is \"\" at \"\".

\

Consider \"\".

\

Apply derivative on each side with respect to \"\".

\

\"\"

\

Consider \"\".

\

Apply derivative on each side with respect to \"\".

\

\"\"   

\

\

Step 2: 

\

Chain rule of derivatives : \"\"

\

Substitute \"\" and \"\" in above expression.

\

\"\"

\

Substitute \"\" in above equation.

\

\"\"

\

The slope is \"\".

\

The point-slope form of a line equation is \"\".

\

Substitute \"\" and the point \"\" in above equation.

\

\"\"

\

The tangent line equation is \"\"  

\

Step 3:  

\

(b)

\

The functions are \"\" and \"\" and the point is \"\".

\

The slope of the tangent line is the derivative of the function at \"\".

\

Consider \"\".

\

Rewrite the expression :

\

\"\"

\

Substitute \"\" in y.

\

\"\"

\

Apply derivative on each side with respect to x.

\

\"\"

\

Substitute \"\" in above equation.

\

\"\"

\

The slope is \"\".

\

The point-slope form of a line equation is \"\".

\

Substitute \"\" and the point \"\" in above equation.

\

\"\"

\

The tangent line equation is \"\"

\

Solution :  

\

The tangent line equation is \"\"

\

.

\

 

\

 

\

 

\